Restklassenring (Z)/mod 80/3,2,5 hoch 1234567/Aufgabe

Man berechne in ${\displaystyle {}\mathbb {Z} /(80)}$ die Elemente

a) ${\displaystyle {}3^{1234567}}$,

b) ${\displaystyle {}2^{1234567}}$,

c) ${\displaystyle {}5^{1234567}}$.