How to cut part of line?

Question

I need to cut line in specific moment, I want to display GPU name, but only name, nothing else.

inxi -Gx | grep Device showing:

Device-2: NVIDIA GK107GLM [Quadro K1100M] vendor: Dell driver: nouveau

I want it to show something like this

NVIDIA GK107GLM [Quadro K1100M]

How to cut this to show only name? Is there a way to print range, in this case from word Device to word vendor.

Please [edit] your question and show the example output of inxi -Gx | grep Device and the expected output, formatted as code. This question is about shell programming / text processing and not specifically related to Ubuntu, so it might better fit on https://stackoverflow.com/ — Bodo, Jul 23 '21 at 07:45
Thanks for your update, however, please check also: "[...] and the expected output, formatted as code." — pLumo, Jul 23 '21 at 08:22
It gives output: Graphics: Device-1 Intel 4th Gen Core Processor Integrated Graphics driver: i915 — Grzegorz Michalak, Jul 23 '21 at 10:10

score 3 · Accepted Answer · answered Jul 23 '21 at 10:45

3

Tryt to do it this way:

inxi -Gx | sed -n 's/.*Device-.*: \(.*\) vendor.*/\1/p'

answered Jul 23 '21 at 10:45

Apomelitos

136

1

Yes, thats it! Thank you very much. Can you describe how this works? This command – Grzegorz Michalak Jul 23 '21 at 10:53
1
Sure.
1. -n param suppresses automatic printing of pattern space(no auto output from sed command)
2. sed is looking for this pattern .*Device-.*: \(.*\) vendor.*
3. /\1/ - sed replaces all the matched line to the first match group (a part of pattern in brackets (.*\))
4. /p param in the end prints the current pattern space( print matched lines)
– Apomelitos Jul 23 '21 at 11:35

score 0 · Answer 2 · answered Jul 23 '21 at 09:01

0

Something like:

D=$(inxi -Gx | grep Device)

if [[ $D =~ ^Device-2:([[:print:]])vendor:([[:print:]])driver:([[:print:]]*)$ ]]
then
echo "Found Device: ${BASH_REMATCH[1]}"
else
echo "Did not find device"
fi

answered Jul 23 '21 at 09:01

Wayne Vosberg

808
4
5

It gives me error syntax error: "(" unexpected (expecting "then") – Grzegorz Michalak Jul 23 '21 at 09:21
What version of bash are you using? (bash --version) – Wayne Vosberg Jul 23 '21 at 09:31
5.0.3. it should work on newer bash? – Grzegorz Michalak Jul 23 '21 at 09:34
It does work with 5.1.4(1). Looking back at the change log regexp matching and BASE_REMATCH may be new as of 5.1. – Wayne Vosberg Jul 23 '21 at 09:38
I can't update bash, its says its newest possible :/ – Grzegorz Michalak Jul 23 '21 at 09:46
try add #!/bin/bash – Jul 23 '21 at 09:47
Its on the first line of script – Grzegorz Michalak Jul 23 '21 at 09:51
maybe you missed semicolon ]]; then – Jul 23 '21 at 11:01
I just realized I have a RaspberryPI with bash 5.0.3(1). It works there as well. Are you sure you entered the if [[ ... ]] line correctly? If so, try adding set -x to the beginning of the script - the output then may provide a clue. – Wayne Vosberg Jul 23 '21 at 13:39

score 0 · Answer 3 · answered Jul 24 '21 at 12:32

0

inxi -Gx | grep -oi nv.*]

inxi -Gx | awk '/Device/{print $2,$3,$4,$5}'

answered Jul 24 '21 at 12:32

HatLess

115
4

score 0 · Answer 4 · answered Jul 24 '21 at 12:49

0

inxi -Gx | grep Device | cut -d ':' -f 2 | sed 's/ vendor//'

This cuts the output into fields using ":" as a delimiter, then it gives you the second field. Use sed then to strip the specific word off the end.

If you know the length then you can cut a range using cut, see man cut for details.

answered Jul 24 '21 at 12:49

pbhj

3,384

I think, that just using -G will strip the vendor part of the string? – pbhj Jul 24 '21 at 12:54

How to cut part of line?

4 Answers4